<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
	xmlns:georss="http://www.georss.org/georss" xmlns:geo="http://www.w3.org/2003/01/geo/wgs84_pos#" xmlns:media="http://search.yahoo.com/mrss/"
		>
<channel>
	<title>Comments on: Results: Who Should Drive Social Media Engagement?</title>
	<atom:link href="http://jackmonson.com/2010/07/06/results-who-should-drive-social-media-engagement/feed/" rel="self" type="application/rss+xml" />
	<link>http://jackmonson.com/2010/07/06/results-who-should-drive-social-media-engagement/</link>
	<description>Social Media &#38; Public Relations Tools and Trends</description>
	<lastBuildDate>Fri, 09 Dec 2011 19:35:48 +0000</lastBuildDate>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>http://wordpress.com/</generator>
	<item>
		<title>By: Richard Becker</title>
		<link>http://jackmonson.com/2010/07/06/results-who-should-drive-social-media-engagement/#comment-137</link>
		<dc:creator><![CDATA[Richard Becker]]></dc:creator>
		<pubDate>Tue, 06 Jul 2010 17:35:19 +0000</pubDate>
		<guid isPermaLink="false">http://jackmonson.com/?p=642#comment-137</guid>
		<description><![CDATA[Jack, 

It seems to me that the most likely outcome would be based on where this question is asked. Perhaps it merely mirrors the makeup of the readership.

Ask the same question at someplace like Ragan and you&#039;ll likely get a different answer.

All my best, 
Rich]]></description>
		<content:encoded><![CDATA[<p>Jack, </p>
<p>It seems to me that the most likely outcome would be based on where this question is asked. Perhaps it merely mirrors the makeup of the readership.</p>
<p>Ask the same question at someplace like Ragan and you&#8217;ll likely get a different answer.</p>
<p>All my best,<br />
Rich</p>
]]></content:encoded>
	</item>
</channel>
</rss>

